Question

A Marchant has 120 liters of oil of one kind, 180 liters of oil of another kind. He wants to sell the oil by filling the two kinds of oil in tins of equal capacity. The greatest capacity of such a tin is

56 litres

60 litres

70 litres

none

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Answer 1

Answer:

Step-by-step explanation:

60litre because 120and180 can be divided by 60.

My answer is correct. Plz mark me as brilliant

Answer 2

Answer:

The third option is correct (60)

Step-by-step explanation:

☞Given:

The merchant has 3 different oils:

• Capacity Of 1 oil= 120 litres
• Capacity Of 2 oil= 180 litres
• Capacity Of 3 oil= 240 litres

So, the greatest capacity of the tin for filling three different types of oil.

☞To find:

• LCM of 120, 180 and 240

☞Solution:

$\boxed{\sf {\red{Apply\: Euclid’s\: division\: lemma\: on \:180 \:and \:120.}}}$

180 = 120 x 1 + 60

120 = 60 x 2 + 0 (here the remainder becomes zero in this step)

Since the divisor at the last step is 60, the HCF (120, 180) = 60.

Now,

• Let’s find the H.C.F of 60 and the third quantity 240.

Applying Euclid’s division lemma, we get

240 = 60 x 4 + 0

And here, since the remainder is 0, the HCF (240, 60) is 60

$\underline{\boxed{\sf{\blue{Therefore, the\: tin \:should\: be\: of\: 60 \:litres.}}}}\pink\bigstar$

тнαηк үσυ

@itzshivani