A ball is released from a height 80 m above the ground. Calculate its velocity just before it strikes the ground. (g = 10 ms-2)
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Answer:
40m/s
Explanation:
s=h= 80m
a=g= 10m/s²
u=0 since it is dropped from rest
from v²-u²=2as
v²-0=2x10x80
v²= 1600
v = square root of 1600
therfore v or final velocity is 40m/s
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