A ball is released from rest and Falls freely it is found to fall through 33 m in 8 second of its journey calculate the value of g
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u=0
s=33m
t=8s
s=ut +(1/2)at^2
33=(0)(8)+(1/2)a(8)(8)
33=32a
a=33/32
a=1.03125m/s^2
Answered by
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d=ut+0.5at^2 so 33=0+0.5*a*64
a=33/32 m/ sec^2
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