Question

a ball is released from the top of height h metres.It takes t seconds to reach the ground. Where is the ball at the time t/2 s?

Answer 1

First case,

Total displacement (s) = h

Time taken = t

Acceleration = a

s = ut+½at²

h = 0+½at² = ½at² ...(i)

Second case,

Displacement = ?

Acceleration = a

Time = t/2

s = ut+½at²

s = 0+½a(t/2)²

s = (½at²)4

s = h/4 .....(from i)