A ball is released from the top of the tower the ratio of work done by force og gravity in 1,2,3 second of the motion of ball is
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force will be the same for all three conditions as mass is not changing so whatever will the ratio of the displacement in 1rst , 2nd and 3rd sec , will be our answer , as
Work = Force × Displacement
and we can use a short trick here ,
whenever a particle is accelerated(constant) from rest the ratio of displacement in 1rst 2nd and 3rd sec = 1:2:3
so the answer will be = 1 : 2 : 3
(u can also calculate the exact values , I.e. 5m , 10m, 15m respectively)
Work = Force × Displacement
and we can use a short trick here ,
whenever a particle is accelerated(constant) from rest the ratio of displacement in 1rst 2nd and 3rd sec = 1:2:3
so the answer will be = 1 : 2 : 3
(u can also calculate the exact values , I.e. 5m , 10m, 15m respectively)
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