a ball is released from top of a tower of height h it takes time t to reach the ground what is the position of the ball after t/3
Answers
Answered by
0
Explanation:
s = ut + 1/2gt²
u = 0, t = t/3, g = 10m/sec²
s = 0 + 1/2*10*t²/9
s = 5/9 t²
it's position from tne ground = h - 5/9t²
Similar questions