Question

A ball is throw with the velocity of 39.2m/s at an angle of 30° with the horizontal .Calculate the maximum height, time of flight & horizontal range of projectile.

Answer 1

H=u^2×sin^2(x)/2g
=(39.2)^2×(1/2)^2/2×9.8
=19.6m


$t = \sqrt{2h \div g}$
$t = \sqrt{2 \times 19.6 \div 9.8}$
t=4 seconds

4H=Rtan (x)
4×19.6=R×tan (30)
$r = 78.4 \times \sqrt{3}$

R=135.7m

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