Question

A ball is thrown at an angle of 30 degree with horizontal with a speed of 30 metre per second calculate maximum height​

Answer 1

Explanation:

x Vot Cos where Vo is the initial velocity, is the launch

angle

y Vo t Sine 2gt 2

The velocities are

Vx Vo Cose

Vy Vo Sine gt

At maximum height, Vy 0 Vo Sine gt

So at maximum height, to Sing

So in this case, e 30, Vo 30m/s and t 1.5s

Vx(1.5s) 30086625981 m/s

Vy(1.5s) 30(0.5) 9.81(1.5) 0.285m/s

So Tan() = 0.285/ 25981001097

Therefore, o 1.9146x10-4 or 0000191

Answer 2

Explanation:

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