Question

A ball is thrown at an angle of 45° with the
horizontal with kinetic energy E. The kinetic
energy at the highest point during the flight is-
(A) Zero
(B) E/2
(C)E
(D) (2)1/2E​

Answer 1

Here, E=1/2 m*v² ----------------- (1)

At highest point v'= vcosФ = v cos 45 = v/√2

 E'= 1/2 m*(v/√2)² = mv²/4  --------------- (2)

From eq 1 and 2

E'= E/2

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