Question

A ball is thrown forward from the top cliff
with velocity 10 m/s. The height of the cliff
above the
ground is 45m. calculate
4 Time to reach the ground
6 Distance from cliff to the ball hitting the ground
6 velocity with which the hall hits the ground
& Direction of ball to the horizontal just before
it hits the ground.
Thalutinn
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Answer 1

Answer:

Horizontal velocity u=10 m/s

Height of the cliff h=20 m

Horizontal distance R=u

g

2h

=10×

10

2×20

=20 m

Answer 2

Answer:

Given :-

Time = 4 sec

G = 10 m/s

u = 0 m/s

To Find :-

Height

Final velocity

Solution :-

We know that

v = u + at

=> v = 0 + (10)(4)

=> v = 0 + 40

=> v = 40 m/s

Now

=> s = (0)(4) + (1/2)(10)(4)(4)

=> s = 0 + (1/2)(80)

=> s = 0 + 40

=> s = 40 m/s