If angle A is a acute and cos A=8/17 thrn cot A is ?
Answers
Answered by
3
Step-by-step explanation:
cos A = 8/17
cos^2 A = 64/289
sin^2 A = 1- cos^2 A
= 1- 64/289
sin A = 15/17
cot A = cos A/ sin A
= 8/17 / 15/17
= 8/15
Answered by
0
Answer:
cot A = tan 1/A cot A=8/17=tan1/A tan^-1 (17/8)=64.79
Step-by-step explanation:
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