Math, asked by shahisuryansh52, 11 months ago

If angle A is a acute and cos A=8/17 thrn cot A is ?

Answers

Answered by ItSdHrUvSiNgH
3

Step-by-step explanation:

cos A = 8/17

cos^2 A = 64/289

sin^2 A = 1- cos^2 A

= 1- 64/289

sin A = 15/17

cot A = cos A/ sin A

= 8/17 / 15/17

= 8/15

Answered by AHMED98
0

Answer:

cot A = tan 1/A       cot A=8/17=tan1/A      tan^-1 (17/8)=64.79

Step-by-step explanation:

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