a ball is thrown from a top of a tower with an initial velocity of 10m/s at an angle of 30° with the horizontal. If it hits the ground at a distance of 17.3m from the base of te tower, Calculate the height of the tower.
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17.3=10cos30°t
17.3=10×√3/2×t
t=17.3×2/10√3
t=2sec.
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