A ball is thrown from the ground at an angle of 45 degree with the horizontal it just clear the wall of 4 m height at a distance of 6 m from the point of projection the distance from the wall at which the ball strikes the ground is
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And.is 18 m
Suppose that it thrown with speed v than do component of v in both directions as v/√2 and v/√2 .
From second eqn vertically
4=v/√2.t-1/2.10t^2
6=v/√2.t-0 ( apply it horizontally there is no acceleration )
t=v/√2.6 put it on above eqn and get and.
kaviya31:
not this answer
plz derive this answer
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