A ball is thrown horizontally at a speed 20 m/s from a height 10 m. Find the time it takes to strike the ground. Also find the horizontal range of throw.
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Answer:
given that
initial speed =v
height 20 m
this speed will remain constant throughout the journey
horizontal components of velocity when
vx=u
v2y=2gh
v2=2*9.8*20. v2=392m2/ s2
v+392=3u
9u2=v2+392
v2=49
v=7m/s.
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