Question

A ball is thrown horizontally with a velocity of 10 metre per second and comes to rest in one minute if the mass of the ball is 200 grams calculate the frictional force exerted by the surface on the ball​

Answer 1

u=10m/s
v=0m/s
t=60s
m=200g=0.2kg
To calculate f
F=m.a
=0.2 *v-u/t
=0.2*-1/6
= -0.033N. HOPE THIS HELPS
PLEASE MARK IT THE BRAINLIEST

Answer 2

u = 10 m/s

v = 0

t = 1 min = 60 sec

m = 200 g = 0.2 kg

F = ?

a = (v-u)/t

= (0-10)/60

= (-10)/60

= (-1)/6 m/s^2

F = ma

= 0.2 × (-1/6)

= 3.33 N