Question

A ball is thrown horizontally with a velocity of 15 m/s what will be vertical and horizontal components of it's velocity in 0.3 second

Answer 1

as there are no force acting on the body in the horizontal direction therefore the horizontal component of the velocity will remain the same . 

in the vertical direction the gravitational force is acting therefore using

 v = u +at  (where u = 0 m/s , t= 0.3 sec , a=g = 9.8 m/sec^2)

 v= 0.3*9.8 

 v= 2.94 m/sec  vertically downward towards earth  velocity after 0.3 seconds.

 the velocity will become inclined to angle 45 with the horizontal when the vertical and horizontal components of the velocity will become equal 

v horizontal = v vertical

 15  = u +at  ( u=0 , a=g=9.8 m/sec)

    15 = 9.8*t

    t = 1.53 seconds

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Answer 2

Explanation:

$Horizontal \: component \: of \: the \: velocity \: will \: remain \: same \: as \: there \: is \: no \: force \: acting \: in \: horizontal \: direction. \\ \therefore \: \red{ \underline{ Horizontal \: component \: of \: velocity \: = 15 \: m \: {s}^{ - 1} } }\\ In \: vertical \: component \: gravitational \: force \: is \: acting \\ \therefore \: v = u + at(where \: u = 0 \: m {s}^{ - 1},a = g = 9.8 \: m {s}^{ - 1} \: and \: t = 0.3 \: s) \\ v = 0 + 9.8 \times 0.3 \\ v = 9.8 \times 0.3 \\ \purple{ \boxed{ \red{v = 2.94m {s}^{ - 1}}}}$

Velocity will be inclined at an angle of 45° when horizontal and vertical component of velocity are equal.

Horizontal (v)=Vertical (v)

15 = u+at

15= 0+9.8*t

15/9.8=t

1.5 s = t

After 1.5 s velocity will be inclined at an angle of 45°.