A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h = −16t2 + 36t + 5. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?
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A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t
seconds is given by the function h=-16t^2+36t+9.
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a. In how many seconds does the ball reach its maximum height? If necessary, round to the nearest hundredth.
Max height is the vertex of the parabola.
Can you find that?
==================
b. What is the maximum height of the ball?
It's the value of h at the time from above.
HOPE , IT HELPS
A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t
seconds is given by the function h=-16t^2+36t+9.
---
a. In how many seconds does the ball reach its maximum height? If necessary, round to the nearest hundredth.
Max height is the vertex of the parabola.
Can you find that?
==================
b. What is the maximum height of the ball?
It's the value of h at the time from above.
HOPE , IT HELPS
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