A ball is thrown is vertically upwards with a velocity of 20m/s . Find the time of flight ,neglecting the air resistance (g= 10m/s^2)
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Answered by
25
Answer:
Using kinematic equation, v = u + a× t, when ball reaches to top of its trajectory, it's velocity becomes zero. Ball is thrown against gravity of earth, therefore a = - g, u = 20 m/s, we can find time of ascend as
0 =20 - 10 × t
20 = 10 × t
t = 20/10 = 2 sec
Time of ascend is same as time of descend = 2 sec.
Time of flight = time of ascend + time of descend
Therefore time of flight = 4 sec.
Answered by
7
Answer:
time is 4 seconds .
Explanation:
given
u = 20 m/s , v = 0 m/s
time of flight is nothing but the time
g = 10 m/s^2
v = u + at
now in further caluclation we get time = 2 sec
time of flight = ascent + desent
2 sec + 2 sec = 4 sec .
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