Question

A ball is thrown straight upward with an initial speed of 12 m/sec after 1 second velocity and displacement will respectively be-

Answer 1

ANSWERS :-

$solution$


v = final velocity
u = intial velocity
h = height
g = gravitational force

v = u - gt

= 12 - 9.8 * 1

= 12 - 9.8

= 2.20 m/sec

so,

v = 2.20 m/sec

h = ut - (1/2)gt²

= 12 * 1 - (1/2) * 9.8 * (1)²

h = 12 - 4.9 = 7.10 m

h = 7.10m

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❤BE BRAINLY ❤
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Answer 2

SOLUTION OF YOUR QUESTION-:

v = final velocity
u = intial velocity
h = height
g = gravitational force

we know that,

v = u - gt

= 12 - 9.8*1

= 12 - 9.8

= 2.20 m/sec 

then,

v = 2.20 m/sec 

h = ut - (1/2)gt²

= 12*1 - (1/2)*9.8*1×1

h = 12 - 4.9 = 7.10 m 

h = 7.10m 《《ANSWER 》》