A ball is thrown up and attains a maximum height of 100 m.it,s initial speed was
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Answered by
18
Hi. ..
Neglecting air resistance (actually relevant in this question), assuming that we're talking about the Earth at sea level with the median acceleration of gravity, and calculating the 100 meters based on the height of the initial velocity measurement, and assuming that the ball is thrown upward at precisely a 90 degree angle with the horizontal, then the problem is simply one of conservation of energy:
g h = (v^2) / 2
Where c is the vertical component of velocity, or speed, in this problem, then we can solve for v:
v = (2 g h)^(1/2)
For 100 m, this is:
44.274 m/s..
Hope this helps u!!
Neglecting air resistance (actually relevant in this question), assuming that we're talking about the Earth at sea level with the median acceleration of gravity, and calculating the 100 meters based on the height of the initial velocity measurement, and assuming that the ball is thrown upward at precisely a 90 degree angle with the horizontal, then the problem is simply one of conservation of energy:
g h = (v^2) / 2
Where c is the vertical component of velocity, or speed, in this problem, then we can solve for v:
v = (2 g h)^(1/2)
For 100 m, this is:
44.274 m/s..
Hope this helps u!!
Answered by
15
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