Question

A ball is thrown up and caught by the thrower after 4 seconds , how high did it go and with which velocity was it thrown

Answer 1

Answer:

v=u+at

v=-10

T=4

u=0

v=-10multiply by 4

v=-40

Answer 2

Answer:

a = -g

v= u+ at

0= u -g(2)

u= 2g = 2(10) = 20m/sec

Initial velocity of ball is 20m/sec.

and because v2-u2 = 2as

0 - (20)2 = -2(10)h

h = 20m

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