Question

Ifa variable assumes the values 1.2.3.4.5 with frequencies as 1, 2, 3, 4, 5, then what is the A.M.?​

Answer 1

Answer:

Step-by-step explanation:

I’m working under the assumption that the frequencies are in a corresponding order to the values

total number of observations = 1 + 2 + 3 + 4 + 5 = 15

weighted average = 1(1/15) + 2(2/15) + 3(3/15) + 4(4/15) + 5(5/15) = 3.666666

{note: it simplifies to (1^2 + 2^2 … 5^2)/15}

The arithmetic mean is 3.666666

Answer 2

HI MATE

HERE IS UR ANSWER

the assumption that the frequencies are in a corresponding order to the values

total number of observations = 1 + 2 + 3 + 4 + 5 = 15

weighted average = 1(1/15) + 2(2/15) + 3(3/15) + 4(4/15) + 5(5/15) = 3.666666

{note: it simplifies to (1^2 + 2^2 … 5^2)/15}

The arithmetic mean is 3.666666

hope it will help you