Question

A ball is thrown up from the top of a tower at 20m/s Velocity. It took 6 seconds to fall to the bottom. For how long was the ball above the tower?
Please answer fast. !!​

Answer 1

Final speed at the top most point (v) = 0

Initial speed (u) = 15 m/s

a = -g = -9.8

Hence, as per the third law of motion,/

v square = u square + 2.a.s

or distance s = (v square - u square)/2.a

or s = (0 - 225)/(2 x -9.8)

or s = 225/19.6 = 11.48 mtrs

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