A ball is thrown up with a certain velocity, and it attains a height of 40m and comes back to the thrower, then the:
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Equation of motion.
v = u + at
v is the final velocity. u is the initial velocity (40 m/s) & t is 2 s. a is the acceleration.
v = 40 + (-10 x 2)
v = 20 m/s
The velocity is 20 m/s upwards.
The value of -g is substituted for a as the object is moving against gravity.
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