Question

A ball is thrown up with a speed of 0.5 m/s.

(i) How high will it go before it begins to fall?​

Answer 1

Answer:

0.0012M

Step-by-step explanation:

SOLUTION:

• DATA:

    velocity=0.5m/s

    final velocity=0

    acceleration due to gravity=g= -9.8m/$s^{2$ (it is taken -ve as body moves  against the gravity)

    h=??

• Formula:

   2gH=V$f^{2}$-V$i^{2}$

• CALCULATION:  

     2(-9.8)H=(0)^2-(0.5)^2

    -19.6H=0-0.25

     H= -0.25/-19.6

     H=0.0012m

• RESULT:

     IT WILL FALL FOR 0.0012METER.