a ball is thrown up with a speed of 15 m/s how high will it go before it gbegins to fall
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hope this helps you.best of luck
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h=(initial velo.)^2 by 2g
h=15*15÷2*9.8
h=225÷19.6
h=11.479 meters
h=15*15÷2*9.8
h=225÷19.6
h=11.479 meters
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