Question

A ball is thrown up with a speed of 8 m/s.
(i) How high willit go before it begins to
fall?
(ii) How long willit take to reach that
height?
take g=10m/s2​

Answer 1

Explanation:

Answer. It will travel height of 11.48 m before it begins to fall.

Answer 2

1)2gh= v^2-u^2

2×10×h=8^2-0^2

20h = 64

h=64/20=32/10=3.2

2) V = u+at

8=0+10×t

8/10=t

0.8=t

please follow me