Question

Calculate the volume occupied by 8.8g of CO2 at 31.1°C and 1 bar pressure. (R=0.083barLK Imol )​

Answer 1

Given :

• Mass of Carbon dioxide = 8.8g
• Temperature = 31.1°C
• Pressure = 1 bar
• Gas constant (R) = 0.083 bar L /( K mol)

To find :

Volume of carbon dioxide

Formula used :

• Mole = Mass ÷ molar mass
• PV = nRT

SOLUTION :

First of all we need to find number of mole of carbon dioxide

• Number of mole = 8.8 ÷ 44

{ Note - molar mass of carbon dioxide = 44 g/mol }

➝ Number of mole = 0.2 mole

• Now convert temperature into Kelvin scale

➝ T = 31.1° C

➝ T = 31.1 + 273

➝ T = 304.1 K

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Now using PV = nRT

$\sf \implies \: 1 bar \times V \: = \: 0.2 mol\times 0.083 \dfrac{bar \:L }{K \: mol} \: \times 304.1K \\ \\ \sf \implies \: V \: = \: 0.2 \times 0.083 \times 304.1 \: L \\ \\ \sf \implies \: V \: = \: \bold{5.04 \: L}$

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ANSWER :

Volume of Carbon dioxide = 5.04 L