a ball is thrown upward from a ground at a tower with a speed of 20m/s.find the height of the tower. If g=10m/s^2
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Answer:
20 m
Explanation:-
v= 0 m/s
u= 20 m/s
g= -10 m/s^2
h= ?
Using 3rd law of motion,
v^2- u^2 = 2gh
0^2- 20^2 = 2*(-10)*h
0- 400 = -20h
-400/-20 = h
h = 20 m
Hope it helps you.
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