Question

A ball is thrown upward from ground with an initial speed of u .the ball is at a height of 80 m at two times the time interval being 6 second

Answer 1

INITIAL SPEED = u

HEIGHT= 80 M

TIME OF ASCEND T1:

0=u-gT1

 

TIME OF DESCEND T2:

0=u-gT2

 

SO T1 + T2 =6

2u/g = 6

u = 29.4 m/s  

 

Thanks