Question

A ball is thrown upward with a speed of 10 m/s. Calculate the speed of the ball after 1 second.

Answer 1

Answer:

Using the equation v = u + at, where ‘v’ is final velocity (what we want to calculate), ‘u’ is the initial velocity (10 m/s in this case), ‘a’ is acceleration (because the ball is being thrown up, acceleration due to gravity will be -9.8 m/s^2), and ‘t’ is the time (in this occasion it’s since the ball was thrown).

So plugging the numbers into the equation:

v = 10 + (-9.8)*(1)

v = 10 - 9.8

v = 0.2 m/s

Explanation:

Hope it helps you...

Answer 2

Answer :

Initial velocity of ball = 10m/s

We have to find speed of ball after 1 s$.$

★ For a body throwing vertically upward, g is taken negative.

Since constant acceleration due to gravity acts in downward direction, we can apply equation of kinematics to solve this question.

First equation of kinematics is given by

• v = u + gt

v denotes final velocity

u denotes initial velocity

g denotes acc. due to gravity

t denotes time

⭆ v = u + gt

⭆ v = 10 + (-10)(1)

⭆ v = 10 - 10

⭆ v = 0 m/s

Cheers!