Question

A ball is thrown upward with a veilocity of 39.2 m/s. Calculate maximum height it reached and time taken to reach it maximum height.

Answer 1

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Answer 2

Answer:

H=78.4m t=2sec

Explanation:

Given data

Vi= 39.2 a=9.8 H= ? t=?

Solution.

for height

2as = Vf^2 - Vi^2

S= V^2 / 2a

S= (39.2 × 39.2) ÷ 2(9.8)

S=78.4m

For time

S= vt t= s/v

t= 78.4÷ 39.2 =2sec

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