Question

a ball is thrown upward with a velocity of 40 m/s then find (a) its velocity after 2s (b) time after which it stops (c) total time from starting if it comes back to its initial position. please send full answer​

Answer 1

Answer:

here you go

Explanation:

velocity after 2 sec.

v=40+(−10)t

=40−10∗2=20m/s

Answer 2

Answer:

a)v=u+at=40-10×2=40-20=20.

b)4s

c)8s