Question

a ball is thrown upward with speed 10m/s from the top of the tower reaches the ground with a speed 20m/s. the height of the tower is ?​

Answer 1

Answer:

2 meter

Explanation:

Good night see you

Answer 2

Answer:

⭐SOLUTION⭐

here,

u= 10 m/sec ( initial velocity)

v= 20 m/sec ( final velovity)

g= -10 m/sec^2 ( acc. due to gravity)

s=? ( height of tower)

By 3rd kinematical eqyation.....

${v}^{2} = {u}^{2} + 2gs \\ \\ s = \frac{ {v}^{2} - {u}^{2} }{2g} \\ \\ s = \frac{ {20}^{2} - {10}^{2} }{2( - 10)} \\ \\ s = \frac{400 - 100}{ - 20} \\ \\ s = \frac{ - 300}{20} \\ \\ s = - 15m$

so, height of tower is 15 metres.......

hope it helps......✌✌