A ball is thrown upwards and reaches a height of 100 m in 2s. What is its initial speed?
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Explanation:
s =100m
v=0m/s
t=2s
Therefore ,
s=ut+1/2at^2
100=2×u+1/2×10×(2)^2
100=2u+1/2×40
100=2u+20
100-20=2u
80=2u......
Therefore ,
u = 40m/s
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