Question

a ball is thrown upwards with a velocity of10m/s.find the maximum height reached by the ball​

Answer 1

Answer:if you assume g to be 9.8m/s^2 then the answer will be 5.10204082 m

If you assume g to be 10m/s^2 then the answer is 5m

Explanation:

Answer 2

Answer:

A ball is thrown upwards with a velocity of 10m/s. The maximum height reached by the ball​ will be $5\ m$

Explanation:

We can solve this problem by using the third law of motion.

• If v is the final velocity of the object, u is the initial velocity of the object, a is the acceleration and s is the distance covered by the object.

• Then, according to the third law of motion,

        $v^{2} - u^{2} =2as$    ...(1)

In the given problem,

$s = h_{max}$  

$a =- g$

(since the ball is thrown upward)

where g is the acceleration due to gravity and $h_{max}$ is the maximum height covered by the ball.

$v = 0$

$u = 10\ m/s$

$g = -10\ m/s^2$

Substitute these values into equation(1)

$0^{2} - 10^{2} =2\times-10\times h_{max}$

$h_{max}= \frac{10^{2} }{20} =5 \ m$