Question

a ball is thrown vertically up with speed of 5m/s attains a max. height H1 and second ball is thrown vertically up from the same point with 10m/s attains a max. height H2.. the ratio of H1 to H2 is?​

Answer 1

Answer:

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Pas 100200

Explanation:

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Answer 2

Answer:

h₂ = 4h₁

Explanation:

Given :-

Speed of first ball = 5 m/s

Speed of second ball = 10 m/s

The both balls attain their max level.

To find :-

Ratio of their heights.

Solution :-

Using the equation of motion,

v² = u² + 2gs

Where,

v - final velocity

u - initial velocity

g - acceleration due to gravity

s - height

Since the balls are thrown from rest, u = 0 m/s

For the first ball,

5² = 0 + 2 × 9.8 × h₁ - (i)

For the second ball,

10² = 0 + 2 × 9.8 × h₂ - (ii)

(0 + 2 × 9.8) gets cancelled

Ratio,

5²/10² = h₁/h₂

25/100 = h₁/h₂

(Cross multiply)

h₂ = 4h₁

Hence, the ratio of their heights is h₂ = 4h₁.