Question

A ball is thrown vertically upward and rises to a height of 126.5 m.calculate the
1)velocity by which the ball was thrown upwards and
2)the time taken by the ball to reach the highest point

Answer 1

Answer:

pls see the attachment

Answer 2

The velocity by which the ball was thrown is 49.79 m/s.

The time taken by the ball to reach the highest point is 5.08 s.

Explanation:

Given the height at which ball is thrown, h = 126.5 m.

1) To calculate the initial velocity of ball by which ball was thrown, use equation of motion,

$v^{2} =u^{2} -2gh$   (upwards thrown)

Here, u is the initial velocity v is final velocity and h is height at which ball reached.

At height 126.5 m (maximum height) , the final velocity is zero.

Substitute the given values, we get

$0 = u^{2} -2\times9.8 m/s^2\times 126.5 m$

$u=\sqrt{2\times9.8 m/s^2\times 126.5 m}$

u = 49.79 m/s

Thus, the velocity by which the ball was thrown is 49.79 m/s.

2) To calculate the time taken by the ball to reach the highest point, use equation of motion

v = u - gt

Substitute the values, we get

$0 = 49.79-9.8m/s^2\times t$

$t=\frac{49.79m/s}{9.8m/s^2}$

t = 5.08 s.

Thus, the time taken by the ball to reach the highest point is 5.08 s.

Learn more : Topic ; Equation of motions

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