Physics, asked by winxbloom387, 10 months ago

A ball is thrown vertically upward and rises to a height of 126.5 m.calculate the
1)velocity by which the ball was thrown upwards and
2)the time taken by the ball to reach the highest point

Answers

Answered by shoaib888
6

this is the answer for the question u assked and timee 18 sec

Attachments:
Answered by Dhananjaytiwarix
20

Answer:

Let velocity of object is u

we know, at 126.5m height object will be rest .

so, final velocity = 0

A/C to kinematics equations,

v² = u² + 2aS

v² = u² +2(-g) × h

0 = u² - 2 × 9.8 x 126.5

u² = 2,479.4

u = √2,479.4  

   = 49.79 m/s

  =  50 m/s

Time taken by the object to reach the highest point is t

v = u + at

0 = 49.79 - 10t

t = 50/10 sec

t = 5 sec

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