Question

A ball is thrown vertically upward and rrisesto a maximum height of 126.5calculate the velocity through which the ball was thrown upward​

Answer 1

Answer:

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Answer 2

Answer:

A ball is thrown vertically upward and rises to a maximum height of 126.5. The velocity through which the ball was thrown upward​ is $50.299 \ m/s$

Explanation:

We can solve this problem by using the third law of motion.

• If v is the final velocity of the object, u is the initial velocity of the object, a is the acceleration and s is the distance covered by the object.

• Then, according to the third law of motion,

        $v^{2} - u^{2} =2as$    ...(1)

       

• In the given problem,

          $s = h_{max}$  

          $a =- g$

        (since the ball is thrown upward)

where g is the acceleration due to gravity and $h_{max}$ is the maximum height covered by the ball.

         $v = 0$

         $g = -10\ m/s^2$

         $h_{max} =126.5\ m$

         $u = ?$

• Substitute these values into equation(1)

         $0^{2} - u^{2} =2\times-10\times 126.5$

         $u = 50.299 \ m/s$