A ball is thrown vertically upward at a speed of 120 m/s. The speed at mid point of its path is ?
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At the top
u=120m/s
v=0
By 3rd equation of motion
v²=u²+2gh. (Considering g=9.8m/s²)
0²=120²-2*9.8*h
h=720m
Now,
Halfway
So, h=(720/2)m
=360m
u=120m/s
h=360
g=9.8m/s²
By 3rd equation
v²=u²+2gh
v²=120²+2*9.8*360
v²=14400+7056
v²=21456
v=√21456
v=146.4787
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u=120m/s
v=0
By 3rd equation of motion
v²=u²+2gh. (Considering g=9.8m/s²)
0²=120²-2*9.8*h
h=720m
Now,
Halfway
So, h=(720/2)m
=360m
u=120m/s
h=360
g=9.8m/s²
By 3rd equation
v²=u²+2gh
v²=120²+2*9.8*360
v²=14400+7056
v²=21456
v=√21456
v=146.4787
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