Question

A ball is thrown vertically upward from the ground with a velocity of 39.2 ms. calculate
A. The maximum heigh to which the ball rises.
B. The time taken by the ball to reach the highest point.

Answer 1

use the formula t=

root under 2h÷g

Answer 2

${v}^{2} = {u}^{2} - 2fs \\ here \: v = 0 \: \: \: u = 39.2 \\ f = 9.8$
0 = 39.2^2 - 2x9.8xS
S= 78.4
$s = ut - \frac{1}{2} f {t}^{2}$
U can get time by solving this equation.