Question

A ball is thrown vertically upward from the ground with the speed of 120m/s. Its speed at the mid point of its path

Answer 1

◆ Answer-

(2) v = 84.8 m/s

◆ Explaination-

# Given-

u = 120 m/s

g = 10 m/s^2

# Solution-

Using Newton's 2nd Kinematics eqn-

v^2 = u^2 + 2as

Here, v = 0, u = 120 m/s, a = -g & s = h, hence

0 = 120^2 - 2×10×h

h = 14400 / 20

h = 720 m

At half this distance, s = h/2 = 360 m,

v^2 = u^2 + 2as

v^2 = 120^2 - 2×10×360

v^2 = 14400 - 7200

v^2 = 7200

v = 84.85 m/s

Velocity of body at midpoint of its path is 84.85 m/s.

Answer 2

Hope it's help you for solving questions.