Question

A ball is thrown vertically upward. it has a speed of 10 metre per second when it has reached one half of its maximum height. how does the ball rise?​

Answer 1

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$ASSALAMUALAIKUM$

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▶put this formulae

 V² = u² - 2gh

After reaching maximum height velocity becomes zero then...

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0 = (10)² - 2 X 10 X $\frac{h}{2}$

h = $\frac{200}{20}$

= 10 meter.

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