One of the exterior angles of a triangle is 100° and the interior opposite angle are equal to each other. What is the measure of each of these two angle?
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Answered by
4
here using exterior angle property
which means exterior angle is equal to the sum of two opposite angle inside a triangle
and both interior opposite angle are equal
therefore
100=angleA+ angle B
100= 2angle A
100/2= anglesA
50= angle A
and angle B =50
which means exterior angle is equal to the sum of two opposite angle inside a triangle
and both interior opposite angle are equal
therefore
100=angleA+ angle B
100= 2angle A
100/2= anglesA
50= angle A
and angle B =50
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nickkaushiknick:
Dude, 100/2 = 50 , not 90 .
Answered by
9
Answer:
50° each
Step-by-step explanation:
Let two opposite interior angles be x each (both angles are equal)
Now,
We know that
Sum of Opposite Interior Angles = Measure of Exterior Angle
∴ x + x = 100
2x = 100
x = 50
∴ Measure of each opposite interior angle is 50°
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