Question

A ball is thrown vertically upward
with a incital velocity of 6 m/sec
and has as mass 7 kg- find the
Kinetic energy of the ball​

Answer 1

Explanation:

kinetic energy=1/2mv^2

kinetic energy of the ball when it is just thrown=1/2×7×6×6=126J

kinetic energy when the ball reaches at the maximum height and velocity becomes 0= 1/2×7×0×0=0

kinetic energy of the ball in midpoint of motion=

2as=v^2-u^u

-2×10×s=0-36

s=1.8

in the midpoint

2as/2=v^2-u^2

-10×0.9=v^2-36

v^2=26

therefore kinetic energy=1/2mv^2=1/2×7×26 =91J

hope this helps.