A ball is thrown vertically upward with a speed of 30m/s.it return back to the hands of thrower after 6s.calculate the maximum height attained by ball. (g=10m/s²)
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it reaches a height of 45m
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kevin26:
wrong
thanks bro
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Answer:45m
Explanation: Initial velocity =30m/s
t=6sec
(Maximum height) h= u*u/2g
=30*30/2*10
=900/20
Therefore h=45
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