Question

A ball is thrown vertically upward with a velocity of 19.6 metre per second find the maximum height reached by the ball and time taken by the ball to reach the maximum height

Answer 1

u=19.6m/s
v=0
g=-9.8m/s^2
v=u+gt
so t=19.6/9.8
t=2sec

v^2-u^2=2gh
h=0-19.6×19.6/(2×-9.8)
h=19.6m

Answer 2

Answer:

19.6 m

Explanation:

u(initial velocity) = 19.6 m/s

at highest point v(final velocity)=0

using v=u+at

0=19.6 - 9.8 * t

t=19.6/9.8= 2s (time to reach max height)

now using v^2 - u^2 = 2as

0 - (19.6)^2 = 2* 9.8 * s

s= 19.6*19.6/2*9.8

s=19.6 m

hope it will help you ;)..