Question

A ball is thrown vertically upward with a velocity of 19.6m/s.find the maximum height reached by the ball

Answer 1

H=19.6^2×sin^290°÷2×9.8
=19.6m
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Answer 2

Explanation:
g = 9.8m/s
u = 19.6m/s
v = 0 (hidden value)
formula used v = u+at
0 = 19.6+9.8t
19.6+9.8t = 0
9.8t = 0-19.6
t = -19.6/9.8
t = 2

now to find height
formula used s = ut+1/2 at^2
19.6*2+1/2*(-9.8*2*2) (g = -9.8 because ball Is going upwards)
(1/2 and 2 cancel)
39.2+(-9.8*2)
39.2-19.6
=19.6m

∴ height=19.6m