If 2a+3b=67.then 4c+5d=
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Answerd Using Speed Maths Technic:
= D (2a) + D (2a - 3b) + D (2a - 3b - 4c)
= D (2a - 3b - 4c + 5d) + D (-3b - 4c + 5d) + D (-4c + 5d) + D (5d)
= 4a² - 12ab - 16ac + 9b² + 20ad + 24bc - 30bd + 16c² - 40cd + 25d²
= 4a² + 9b² + 16c² + 25d² + 24bc - 40cd + 16ac +20ad - 30bd
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